Practice problem
If 3x=105\frac{3}{x}=\frac{10}{5}x3=510, then how can we solve for xxx?
(5)⋅(x)=30\left(5\right)\cdot\left(x\right)=30(5)⋅(x)=30, thus x=6x=6x=6
(3)⋅(5)=10⋅(x)\left(3\right)\cdot\left(5\right)=10\cdot\left(x\right)(3)⋅(5)=10⋅(x), thus x=1510=32x=\frac{15}{10}=\frac{3}{2}x=1015=23
(10+x)=(3+5)(10+x)=(3+5)(10+x)=(3+5), thus x=(8−10)=−2x=(8-10)=-2x=(8−10)=−2
(5+x)=(10+3)(5+x)=(10+3)(5+x)=(10+3), thus x=(13−5)x=(13-5)x=(13−5)
Type a concept, like “slope” or “photosynthesis”.
