Practice problem
If f(x)={3x+1when x≥02x−1when x<0,f(x)=\begin{cases} 3x+1 & \text{when }x\geq0\\2x-1 &\text{when } x<0\end{cases},f(x)={3x+12x−1when x≥0when x<0, find f(3)f(3)f(3) and f(−1)f(-1)f(−1).
f(3)=5f(3)=5f(3)=5
f(3)=10f(3)=10f(3)=10
f(−1)=−2f(-1)=-2f(−1)=−2
f(−1)=−3f(-1)=-3f(−1)=−3
Type a concept, like “slope” or “photosynthesis”.
