Practice problem
The volume of a circular cone is V=13(π)r2hV=\frac{1}{3}(\pi)r^2hV=31(π)r2h. Solve for hhh.
3Vrπ\frac{3V}{r\pi}rπ3V
π3r2\frac{\pi}{3r^2}3r2π
3Vr2π\frac{3V}{r^2\pi}r2π3V
V3r2π\frac{V}{3r^2\pi}3r2πV
Type a concept, like “slope” or “photosynthesis”.
