Practice problem
Find the derivative. y=(1+x)2arctanxy=(1+x)^2\arctan xy=(1+x)2arctanx
y′=2arctanx+(1+x)21−x2y'=2\arctan x+\frac{(1+x)^2}{1-x^2}y′=2arctanx+1−x2(1+x)2
y′=2arctanx(1+x)21+x2y'=\frac{2\arctan x(1+x)^2}{1+x^2}y′=1+x22arctanx(1+x)2
y′=2(1+x)arctanxy'=2(1+x)\arctan xy′=2(1+x)arctanx
y′=2(1+x)arctanx+(1+x)21+x2y'=2(1+x)\arctan x+\frac{(1+x)^2}{1+x^2}y′=2(1+x)arctanx+1+x2(1+x)2
Type a concept, like “slope” or “photosynthesis”.
