Practice problem
Find the derivative. f(x)=e−csc−1xf(x)=e^{-\csc^{-1}x}f(x)=e−csc−1x
f′(x)=e−csc−1xx2f'(x)=\frac{e^{-\csc^{-1}x}}{x^2}f′(x)=x2e−csc−1x
f′(x)=e−csc−1xxx2−1f'(x)=\frac{e^{-\csc^{-1}x}}{x\sqrt{x^2-1}}f′(x)=xx2−1e−csc−1x
f′(x)=e−csc−1x−1xx2−1f'(x)=\frac{e^{-\csc^{-1}x-1}}{x\sqrt{x^2-1}}f′(x)=xx2−1e−csc−1x−1
f′(x)=−e−csc−1xx1−x2f'(x)=-\frac{e^{-\csc^{-1}x}}{x\sqrt{1-x^2}}f′(x)=−x1−x2e−csc−1x
Type a concept, like “slope” or “photosynthesis”.
