Practice problem
Find the derivative. arctan(xy)=1+xy\arctan(xy)=1+xyarctan(xy)=1+xy
y′=tan(xy)y'=\tan(xy)y′=tan(xy)
y′=−yxy'=-\frac yxy′=−xy
y′=11+x2y2y'=\frac{1}{1+x^2y^2}y′=1+x2y21
y′=x2y2−11+xyy'=x^2y^2-\frac{1}{1+xy}y′=x2y2−1+xy1
Type a concept, like “slope” or “photosynthesis”.
