Practice problem
Find the derivative. f(x)=arcsinesinxf(x)=\arcsin{e^{\sin x}}f(x)=arcsinesinx
f′(x)=esinxcosx1−e2sinxf'(x)=\frac{e^{\sin x}\cos x}{\sqrt{1-e^{2\sin x}}}f′(x)=1−e2sinxesinxcosx
f′(x)=11−e2sinxf'(x)=\frac{1}{\sqrt{1-e^{2\sin x}}}f′(x)=1−e2sinx1
f′(x)=cosxesinx1−e2sinxf'(x)=\frac{\cos x}{e^{\sin x}\sqrt{1-e^{2\sin x}}}f′(x)=esinx1−e2sinxcosx
f′(x)=esinxcosx1+e2sinxf'(x)=\frac{e^{\sin x}\cos x}{1 +e^{2\sin x}}f′(x)=1+e2sinxesinxcosx
Type a concept, like “slope” or “photosynthesis”.