Practice problem
Find the second derivative. y=arcsin(ex)y=\arcsin(e^x)y=arcsin(ex)
y′′=ex1−e2xy''=e^x\sqrt{1-e^{2x}}y′′=ex1−e2x
y′′=ex(1−e2x)32y''=\frac{e^x}{(1-e^{2x})^{\frac32}}y′′=(1−e2x)23ex
y′′=ex1−e2xy''=\frac{e^x}{1-e^{2x}}y′′=1−e2xex
y′′=ex1−e2xy''=\frac{e^x}{\sqrt{1-e^{2x}}}y′′=1−e2xex
Type a concept, like “slope” or “photosynthesis”.
