Practice problem
Find the derivative of y=xsinh−1(x3)y=x\sinh^{-1}\bigg(\frac{x}3\bigg)y=xsinh−1(3x)
y′=sinh(x3)+x3x2+1y'=\sinh\left(\frac{x}3\right)+\frac{x}{3\sqrt{x^2+1}}y′=sinh(3x)+3x2+1x
y′=sinh(x3)+xx2+1y'=\sinh\left(\frac{x}3\right)+\frac{x}{\sqrt{x^2+1}}y′=sinh(3x)+x2+1x
y′=sinh(x3)+13xcosh(x3)y'=\sinh\left(\frac{x}3\right)+\frac13x\cosh\left(\frac{x}3\right)y′=sinh(3x)+31xcosh(3x)
y′=x3x2+1y'=\frac{x}{3\sqrt{x^2+1}}y′=3x2+1x
Type a concept, like “slope” or “photosynthesis”.
