Practice problem
Find the derivative of h(x)=sinh−1(coshx)h(x)=\sinh^{-1}(\cosh x)h(x)=sinh−1(coshx)
h′(x)=sinhx(coshx)2+1h'(x)=\frac{\sinh x}{\sqrt{(\cosh x)^2+1}}h′(x)=(coshx)2+1sinhx
h′(x)=coshx(coshx)2+1+xh'(x)=\frac{\cosh x}{\sqrt{(\cosh x)^2+1}}+xh′(x)=(coshx)2+1coshx+x
h′(x)=1(coshx)2+1h'(x)=\frac{1}{\sqrt{(\cosh x)^2+1}}h′(x)=(coshx)2+11
h′(x)=x(coshx)2+1h'(x)=\frac{x}{\sqrt{(\cosh x)^2+1}}h′(x)=(coshx)2+1x
Type a concept, like “slope” or “photosynthesis”.
