Practice problem
Find the derivative. h(t)=ln4t2−34t2+3h(t)=\ln\frac{\sqrt{4t^2-3}}{\sqrt{4t^2+3}}h(t)=ln4t2+34t2−3
h′(t)=4t2−316t4−9h'(t)=\frac{\sqrt{4t^2-3}}{16t^4-9}h′(t)=16t4−94t2−3
h′(t)=8t−216t4−9h'(t)=\frac{8t-2}{16t^4-9}h′(t)=16t4−98t−2
h′(t)=4t2+34t2−3h'(t)=\sqrt{\frac{4t^2+3}{4t^2-3}}h′(t)=4t2−34t2+3
h′(t)=24t16t4−9h'(t)=\frac{24t}{16t^4-9}h′(t)=16t4−924t
Type a concept, like “slope” or “photosynthesis”.
