Practice problem
Find the second derivative. g(t)=2lnt2t2g(t)=\frac{2\ln t^2}{t^2}g(t)=t22lnt2
g′′(t)=lnt2−1t6g''(t)=\frac{\ln t^2-1}{t^6}g′′(t)=t6lnt2−1
g′′(t)=12lnt2−20t4g''(t)=\frac{12\ln t^2-20}{t^4}g′′(t)=t412lnt2−20
g′′(t)=8−4tlnt2t4g''(t)=\frac{8-4t\ln t^2}{t^4}g′′(t)=t48−4tlnt2
g′′(t)=6lnt2−16t6g''(t)=\frac{6\ln t^2-16}{t^6}g′′(t)=t66lnt2−16
Type a concept, like “slope” or “photosynthesis”.
