Practice problem
Find the derivative. f(x)=2+ln(4x3)x2f(x)=\frac{2+\ln(4x^3)}{x^2}f(x)=x22+ln(4x3)
f′(x)=−1−2ln(4x3)x3f'(x)=\frac{-1-2\ln(4x^3)}{x^3}f′(x)=x3−1−2ln(4x3)
f′(x)=3−ln(4x3)x3f'(x)=\frac{3-\ln(4x^3)}{x^3}f′(x)=x33−ln(4x3)
f′(x)=5+ln(4x3)x2f'(x)=\frac{5+\ln(4x^3)}{x^2}f′(x)=x25+ln(4x3)
f′(x)=3+2x+xln(4x3)x3f'(x)=\frac{3+2x+x\ln(4x^3)}{x^3}f′(x)=x33+2x+xln(4x3)
Type a concept, like “slope” or “photosynthesis”.
