Yankees player Babe Ruth could hit a baseball with the initial velocity v0v_{0} of 150150 feet per second! Assuming he hit the ball at an initial height of h0=5h_{0}=5 feet, use the equation h(t)=−12gt2+v0t+h0h(t)= -\frac12gt^2+v_{0}t+h_{0} to find out how many seconds passed before the ball hit the ground. Use 3232 as the force of gravity gg.

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