A new superhero action movie is being filmed and the film crew is planning a stunt. In this stunt, a stunt double will jump high into the air while a sports car zooms beneath his trajectory. The crew wants to know how many seconds the jumper will be in the air so they can calculate how fast the sports car has to drive to make it in time. \\ If the stunt double jumps with an initial velocity of 2424 feet per second (v0=24v_{0}=24) from ground level (h0=0h_{0}=0), how many seconds will pass before he hits the ground? \\ Use the equation h(t)=−12gt2+v0t+h0h(t)= -\frac12gt^2+v_{0}t+h_{0}, which gives the height of an object in projectile motion, and let the force of gravity gg be 3232 feet per second.

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