Practice problem
If f(x)=ax2+bx+cf(x)=ax^2+bx+cf(x)=ax2+bx+c is a quadratic function with a<0a<0a<0, what is the xxx-value of the vertex?
x=−bax=-\frac{b}{a}x=−ab
x=−2abx=-\frac{2a}{b}x=−b2a
x=−b2ax=-\frac{b}{2a}x=−2ab
x=0x=0x=0
Type a concept, like “slope” or “photosynthesis”.