Practice problem
Find the equation of the line that is perpendicular to the line −13x+y=5-\frac{1}{3}x+y=5−31x+y=5 and passes through the point (2,4)(2,4)(2,4)
y=−3x−5y=-3x-5y=−3x−5
y=3x+10y=3x+10y=3x+10
y=13x+10y=\frac{1}{3}x+10y=31x+10
y=−3x+10y=-3x+10y=−3x+10
Type a concept, like “slope” or “photosynthesis”.