Practice problem
Find the equation of a quadratic function that has zeros at x=−1x=-1x=−1 and x=1x=1x=1.
f(x)=x2+2x−1f(x)=x^2+2x-1f(x)=x2+2x−1
f(x)=x2+x−1f(x)=x^2+x-1f(x)=x2+x−1
f(x)=x2−1f(x)=x^2-1f(x)=x2−1
f(x)=x2+1f(x)=x^2+1f(x)=x2+1
Type a concept, like “slope” or “photosynthesis”.