Practice problem
Use the Mean Value Theorem for the function f(x)=1x2−1f(x)=\frac{1}{x^2-1}f(x)=x2−11 on the interval [2,2.1][2,2.1][2,2.1].
c=0.186351c=0.186351c=0.186351
c=2.0013c=2.0013c=2.0013
c=2.04972c=2.04972c=2.04972
Function is not continuous.
Function is not differentiable.
Type a concept, like “slope” or “photosynthesis”.
