Practice problem
Use the Mean Value Theorem for the function f(x)=1ex2f(x)=\frac{1}{e^{x^2}}f(x)=ex21 on the interval [−2,2][-2,2][−2,2].
c=−e2c=-e^2c=−e2
c=0c=0c=0
c=e2c=e^2c=e2
Function is not continuous.
Function is not differentiable.
Type a concept, like “slope” or “photosynthesis”.
