Practice problem
Use the Mean Value Theorem for the function f(x)=4−x2f(x)=\sqrt{4-x^2}f(x)=4−x2 on the interval [0,2][0,2][0,2].
c=−2c=-\sqrt2c=−2
c=0c=0c=0
c=2c=\sqrt2c=2
Function is not continuous.
Function is not differentiable.
Type a concept, like “slope” or “photosynthesis”.
