Practice problem
Solve using elimination: {4y=15(x−5)28y=28−5x\begin{cases} 4y=\frac{1}{5}(x-5)^2\\ 8y=\frac{2}{8}-5x \end{cases}{4y=51(x−5)28y=82−5x
(15,5)(15,5)(15,5)
(.05,0)(.05,0)(.05,0)
(0,1.25)(0,1.25)(0,1.25)
No Real Solution.
Type a concept, like “slope” or “photosynthesis”.
