Solve equation (A) and plug the result into expression (B). 23−6x8=12(A)45+35x(B)\begin{array}{lc} \frac{2}{3}-\frac{6x}{8}=\frac{1}{2}&\quad\small{(A)}\\ \frac{4}{5}+\frac{3}{5}x&\quad\small{(B)} \end{array}

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