Practice problem
Solve the system of equation: {(1+x)2+12+y2=41x2+2x−3=0\begin{cases} \left(1+x\right)^2+12+y^2=41\\ x^2+2x-3=0 \end{cases}{(1+x)2+12+y2=41x2+2x−3=0
(1, -3), (-1, -5)
(1, 5), (1, -5), (-3, 5), (-3, -5)
(−12-\frac{1}{2}−21, 5), (12\frac{1}{2}21, -5), (1, 5), (1, -5)
(3, -5), (3, 5)
Type a concept, like “slope” or “photosynthesis”.