Practice problem
Find the limit of the following function using substitution: \\ limx→−4x2+x−12x+4=\lim\limits_{x \to -4} \frac{x^2+x-12}{x+4}=x→−4limx+4x2+x−12=
limx→−4f(x)=0\lim\limits_{x \to -4}f(x)=0x→−4limf(x)=0
limx→−4f(x)=3\lim\limits_{x \to -4}f(x)=3x→−4limf(x)=3
limx→−4f(x)=−7\lim\limits_{x \to -4}f(x)=-7x→−4limf(x)=−7
DNE
Type a concept, like “slope” or “photosynthesis”.