Practice problem
Solve for xxx in terms of bbb and ccc, if b≠0b\neq0b=0. 2x⋅bc=52x\cdot\frac{b}{c}=52x⋅cb=5
x=10cbx=\frac{10c}{b}x=b10c
x=5c2bx=\frac{5c}{2b}x=2b5c
x=2×5bcx=2\times\frac{5b}{c}x=2×c5b
x=10bcx=\frac{10b}{c}x=c10b
Type a concept, like “slope” or “photosynthesis”.
