Probability: Inclusion-Exclusion Principle

Andrew decided to run a simulation to find the probability of him being late for work. He decided to determine this by considering the probability of two events. Event A: He gets stuck in rush hour traffic. Event B: He sleeps through his alarm. Andrew discovers that $P(A)=0.25$ and $P(B)=0.33$. Andrew will be late in the case where $(A\cup B)$. What is the probability of Andrew being late? Assume that the events $A$ and $B$ are independent. $\\$ hint: The inclusion-exclusion principle for two events in a probability space states that $P(A\cup B) = P(A)+P(B)-P(A \cap B)$