Practice problem
What is the area of this circle in terms of ddd?
A = π4d2\text{A = }\dfrac{\pi}{4}d^{2}A = 4πd2
A = π4d\text{A = }\dfrac{\pi}{4}dA = 4πd
A = π2d\text{A = }\dfrac{\pi}{2}dA = 2πd
Not enough information.
Type a concept, like “slope” or “photosynthesis”.
