Practice problem
Which of the following is equivalent to x2+3x+2x÷33x2−3x−18\frac{x^2+3x+2}{x}\div\frac{3}{3x^2-3x-18}xx2+3x+2÷3x2−3x−183 assuming xxx and 3x2−3x−183x^2-3x-183x2−3x−18 are nonzero.
x+1x(x−3)\frac{x+1}{x(x-3)}x(x−3)x+1
(x+1)(x−3)3x\frac{(x+1)(x-3)}{3x}3x(x+1)(x−3)
(x+1)(x+2)(x−3)3x\frac{(x+1)(x+2)(x-3)}{3x}3x(x+1)(x+2)(x−3)
(x+1)(x+2)2(x−3)x\frac{(x+1)(x+2)^2(x-3)}{x}x(x+1)(x+2)2(x−3)
Type a concept, like “slope” or “photosynthesis”.
