Solve equation (A) for yy and plug the result into expression (B). 3cos⁡x−3y=6(A)4cos⁡x−8y(B)\begin{array}{lc} 3\cos x-3y=6&\quad\small{(A)}\\ \frac{4\cos x-8}{y}&\quad\small{(B)} \end{array}

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