Practice problem
Find the value(s) of xxx such that 2−∣x∣=12-|x|=12−∣x∣=1.
x=0x=0x=0
x=±1x=\pm1x=±1
x=±2x=\pm2x=±2
x=±3x=\pm3x=±3
Type a concept, like “slope” or “photosynthesis”.
