Practice problem
Find the value(s) of xxx such that 2÷∣2x∣=22\div|2x| = 22÷∣2x∣=2.
x=±1x=\pm1x=±1
x=±2x=\pm2x=±2
x=±12x=\pm\frac12x=±21
x=±3x=\pm3x=±3
Type a concept, like “slope” or “photosynthesis”.