The Escape Velocity From A Star Is Given By This Equation : Ve=2GMR{\text{V}}_e=\sqrt{\frac{2\text{GM}}{R}} Where, Ve=Escape VelocityG=Gravitational Constant=6.673×10−11Nm2kg−2M=Mass of The StarR=Radius of The Star\begin{align} \text{V}_e&=\text{Escape Velocity}\\ \text{G}&=\text{Gravitational Constant}\\ &=6.673 \times 10^{-11} \text{N}m^2kg^{-2}\\ \text{M}&=\text{Mass of The Star}\\ \text{R}&=\text{Radius of The Star} \end{align} Now we have to determine the Escape Velocity (in km/s) from a Black Hole which has an enormous Mass of 6×1030kg6 \times 10^{30} kg but a Radius of only5.00475 km5.00475\text{ km} Clue: Plug the Mass and Radius in the Equation above. Don't forget to convert from kilometer to meter and vice versa!

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