Solve the system of equations using substitution. 8x−y−2z=27−x+2y+9z=162x−4y−2z=0\begin{gather} 8x-y-2z=27\\ -x+2y+9z=16\\ 2x-4y-2z=0 \end{gather} If the solution is (x,y,z)(x,y,z), enter in the value of 100x+10y+z100x + 10y+z as your answer.

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