Circumference and Convenience\text{Circumference and Convenience}

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Tau

Tomorrow (June 2828) is Tau Day, a holiday celebrating the constant τ\tau, which is equal to 2π=6.2831853…2\pi=6.2831853….

Many mathematicians prefer τ\tau to π\pi because it simplifies several circle formulas; for example, the circumference CC of a circle can be represented as the product of its radius RR and τ\tau: C=τRC=\tau R Entire manifestos have even been written about Tau.

Notably, τ\tau is used for convenience in 22 dimensional spaces (especially with circles, which are really just 22 dimensional spheres). That’s pretty useful.

But why stop there? Let’s look at some more dimensions!

Number of DimensionsVolumeSurface Area2πR22πR343πR34πR2412π2R42π2R35815π2R583π2R4616π3R6π3R5716105π3R71615π3R68124π4R813π4R7\begin{array}{c c c} \text{Number of Dimensions} & \text{Volume} & \text{Surface Area} \\ \hline 2 & \pi R^2 & 2\pi R \\ 3 & \frac{4}{3}\pi R^3 & 4\pi R^2 \\ 4 & \frac{1}{2}\pi^2 R^4 & 2\pi^2 R^3 \\ 5 & \frac{8}{15} \pi^2 R^5 & \frac{8}{3}\pi^2 R^4 \\ 6 & \frac{1}{6}\pi^3 R^6 & \pi^3 R^5 \\ 7 & \frac{16}{105}\pi^3 R^7 & \frac{16}{15}\pi^3 R^6 \\ 8 & \frac{1}{24}\pi^4 R^8 & \frac{1}{3}\pi^4 R^7 \end{array}

Note that we typically call the volume of a circle the area and the surface area of a circle the circumference. Of course, thinking of spheres in multiple dimensions is a little weird, but you don’t actually need to know what these objects look like to determine their properties!

We can look at the surface areas to see that there is always some constant multiplied by a power of RR. In our beloved two dimensional sphere (a circle!), this constant is 2π2\pi, which is τ\tau. So if one of the purposes of τ\tau is convenience, let’s look at its analogs in other dimensions!

For example, the “tau” of the 5th5^{th} dimension is 83π2\frac{8}{3}\pi^2 because this is the constant that appears before the power of RR (which here is R4R^4). This is also the second such constant to be divisible by π2\pi^2.

Let octoπocto\pi be the first surface area “tau” (constant) value that is divisible by π8\pi^8. What is the exact value of this constant?
For this problem, you will need to come up with a formula (either recursive or closed form) for the surface area as a function of the number of dimensions and then apply it to the number of dimensions that correspond to the first appearance of π8\pi^8 in any surface area. The information about volumes can help!

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