Practice problem
Find the inverse (A−1A^{-1}A−1) of matrix A:
A=[6812]A = \begin{bmatrix} 6 & 8 \\ 1 & 2 \end{bmatrix}A=[6182]
A−1=[−21232−14]A^{-1} = \begin{bmatrix} -2 & \frac{1}{2} \\ \frac{3}{2} & -\frac{1}{4} \end{bmatrix}A−1=[−22321−41]
A−1=[32−2−1412]A^{-1} = \begin{bmatrix} \frac{3}{2} & -2 \\ -\frac{1}{4} & \frac{1}{2} \end{bmatrix}A−1=[23−41−221]
A−1=[2−8−16]A^{-1} = \begin{bmatrix} 2 & -8 \\ -1 & 6 \end{bmatrix}A−1=[2−1−86]
A−1=[12−2−1432]A^{-1} = \begin{bmatrix} \frac{1}{2} & -2 \\ -\frac{1}{4} & \frac{3}{2} \end{bmatrix}A−1=[21−41−223]
No Inverse
Type a concept, like “slope” or “photosynthesis”.