Practice problem
Find the inverse of matrix A:
A=[1274]A = \begin{bmatrix} 1 & 2 \\ 7 & 4 \end{bmatrix}A=[1724]
A−1=[−2515710−110]A^{-1} = \begin{bmatrix} -\frac{2}{5} & \frac{1}{5}\\ \frac{7}{10} & -\frac{1}{10} \end{bmatrix}A−1=[−5210751−101]
A−1=[2515710110]A^{-1} = \begin{bmatrix} \frac{2}{5} & \frac{1}{5}\\ \frac{7}{10} & \frac{1}{10} \end{bmatrix}A−1=[5210751101]
A−1=[15−25−110710]A^{-1} = \begin{bmatrix} \frac{1}{5} & -\frac{2}{5}\\ -\frac{1}{10} & \frac{7}{10} \end{bmatrix}A−1=[51−101−52107]
A−1=[4−2−71]A^{-1} = \begin{bmatrix} 4 & -2 \\ -7 & 1 \end{bmatrix}A−1=[4−7−21]
No Inverse
Type a concept, like “slope” or “photosynthesis”.