Practice problem
Find the inverse (A−1A^{-1}A−1) for matrix AAA:
A=[10−6−42]A = \begin{bmatrix} 10 & -6 \\ -4 & 2 \end{bmatrix}A=[10−4−62]
A−1=[−321252−1]A^{-1} = \begin{bmatrix} -\frac{3}{2} & \frac{1}{2}\\ \frac{5}{2} & -1 \end{bmatrix}A−1=[−232521−1]
A−1=[26410]A^{-1} = \begin{bmatrix} 2 & 6 \\ 4 & 10 \end{bmatrix}A−1=[24610]
A−1=[−32−12−52−1]A^{-1} = \begin{bmatrix} -\frac{3}{2} & -\frac{1}{2}\\ -\frac{5}{2} & -1 \end{bmatrix}A−1=[−23−25−21−1]
A−1=[−12−32−1−52]A^{-1} = \begin{bmatrix} -\frac{1}{2} & -\frac{3}{2} \\ -1 & -\frac{5}{2} \end{bmatrix}A−1=[−21−1−23−25]
No Inverse
Type a concept, like “slope” or “photosynthesis”.