Practice problem
Find the inverse (A−1A^{-1}A−1) of matrix A:
A=[3210]A = \begin{bmatrix} 3 & 2 \\ 1 & 0 \end{bmatrix}A=[3120]
A−1=[0112−32]A^{-1} = \begin{bmatrix} 0 & 1 \\ \frac{1}{2} & -\frac{3}{2} \end{bmatrix}A−1=[0211−23]
A−1=[10−3212]A^{-1} = \begin{bmatrix} 1 & 0 \\ -\frac{3}{2} & \frac{1}{2} \end{bmatrix}A−1=[1−23021]
A−1=[0−2−13]A^{-1} = \begin{bmatrix} 0 & -2 \\ -1 & 3 \end{bmatrix}A−1=[0−1−23]
No Inverse
Type a concept, like “slope” or “photosynthesis”.