Practice problem
Simplify loga(12)+loga(12)\log_{a}(12) + \log_{a}(12)loga(12)+loga(12) when a>1a>1a>1.
loga(24)\log_{a}(24)loga(24)
loga(1)=0\log_{a}(1) = 0loga(1)=0
loga(144)\log_{a}(144)loga(144)
log12(a)\log_{12}(a)log12(a)
Type a concept, like “slope” or “photosynthesis”.