Practice problem
Which of the following lines is perpendicular to y=76x+9y=\frac{7}{6}x+9y=67x+9?
y=67x−4y=\frac{6}{7}x-4y=76x−4
y=−4249x+1y=\frac{-42}{49}x+1y=49−42x+1
y=7x−6y=7x-6y=7x−6
y=−76+3y=\frac{-7}{6}+3y=6−7+3
Type a concept, like “slope” or “photosynthesis”.