Practice problem
Solve for xxx: log2(3x+1)+log2(−x−5)=log28\log_{2} (3x+1) + \log_{2} (-x-5) = \log_{2}8log2(3x+1)+log2(−x−5)=log28
−133-\dfrac{13}{3}−313
133\dfrac{13}{3}313
−1-1−1
No Solution
Type a concept, like “slope” or “photosynthesis”.