Let log⁡a(9)=0.7891,log⁡a(2)=0.0231, and log⁡a(4)=0.4556\log_{a}(9)= 0.7891, \log_{a}(2)= 0.0231, \text{ and } \log_{a}(4)=0.4556. Using these values, evaluate log⁡a36\log_{a} 36.

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