Practice problem
Solve for xxx: log5(x+1)+log5(2x+3)=log513\log_{5}(x+1)+\log_{5}(2x+3) = \log_{5}13log5(x+1)+log5(2x+3)=log513
−5+1054\dfrac {-5 + \sqrt{105}}{4}4−5+105
−5−1054\dfrac {-5 - \sqrt{105}}{4}4−5−105
5+1054\dfrac {5 + \sqrt{105}}{4}45+105
No Solution
Type a concept, like “slope” or “photosynthesis”.
