Practice problem
Find the equation of a line parallel to y=23x+4y=\frac{2}{3}x+4y=32x+4, and passing through the point (3,9)(3,9)(3,9).
y=−23x+11y = \frac{-2}{3}x+11y=3−2x+11
y=23x+4y = \frac{2}{3}x+4y=32x+4
y=32x+92y = \frac{3}{2}x+\frac{9}{2}y=23x+29
y=23x+7y = \frac{2}{3}x+7y=32x+7
Type a concept, like “slope” or “photosynthesis”.