Practice problem
Find the value of α\alphaα that makes the following lines parallel. y=13x−6y = \frac{1}{3}x-6y=31x−6 y=6αx+7y = \frac{6}{\alpha}x+7y=α6x+7
α=2\alpha = 2α=2
α=18\alpha = 18α=18
α=3\alpha = 3α=3
α=12\alpha = 12α=12
Type a concept, like “slope” or “photosynthesis”.