Practice problem
Solve for xxx: log39x−log3x3=3\log_{3}9x - \log_{3}x^3 = 3log39x−log3x3=3
13\sqrt{ \dfrac {1}{3}}31
±13\pm\sqrt{ \dfrac {1}{3}}±31
3\sqrt{3}3
103\dfrac {10}{3}310
Type a concept, like “slope” or “photosynthesis”.
