Define a sequence {an}\{a_n\} by a1=a2=1,a3=2a_1=a_2=1, a_3 = 2 and

an+an−3=an−2+an−1a_n + a_{n-3} = a_{n-2}+a_{n-1}

for n>3n > 3. Find all positive integers nn such that an=2018a_n = 2018.

Source: Lexington Math Tournament

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