Practice problem
Find the equation of a line passing through the point (−6,5)(-6,5)(−6,5) and that is parallel to the line 3x−5y=93x-5y=93x−5y=9.
y=35xy=\dfrac{3}{5}xy=53x
y=−35x+75y=-\dfrac{3}{5}x+\dfrac{7}{5}y=−53x+57
y=35x+435y=\dfrac{3}{5}x+ \dfrac{43}{5}y=53x+543
y=−53x+435y=-\dfrac{5}{3}x+ \dfrac{43}{5}y=−35x+543
Type a concept, like “slope” or “photosynthesis”.