Practice problem
Find a quadratic polynomial ppp such that p(0)=0p(0) = 0p(0)=0, p(2)=1212p(2) = \frac{121}{2}p(2)=2121, and p(8)=11p(8) = 11p(8)=11.
p(x)=−7716x2+1658xp(x) = -\frac{77}{16}x^2 + \frac{165}{8}xp(x)=−1677x2+8165x
p(x)=−7716x2+3198xp(x) = -\frac{77}{16}x^2 + \frac{319}{8}xp(x)=−1677x2+8319x
p(x)=−7716x2+1658x+8p(x) = -\frac{77}{16}x^2 + \frac{165}{8}x + 8p(x)=−1677x2+8165x+8
p(x)=7716x3−3198x2p(x) = \frac{77}{16}x^3 - \frac{319}{8}x^2p(x)=1677x3−8319x2
Type a concept, like “slope” or “photosynthesis”.
